Three Fun Christmas Math Activities to Enjoy with Your Kids on New Year’s Eve

To do this, we will use the following model, taken from the site jesuisannimateur.fr : We have two Santa Clauses worth 14; a snowman – a Santa Claus is worth 3; an elf + a snowman is worth 11.

Could you find the last result? The goal in the end is to have the value of each character.

Well, it's true that it was rather simple, but at least you have the basis for the rest, which will be a little more difficult. Let's imagine that the results obtained are candy. The goal is to know how many candies we will have left at the end of the three calculations.

First calculation:

If we have two Santas and add three snowmen, how many candies will we have?

Second calculation:

If we now have twenty Santas, from which we subtract seven elves which we will first multiply by a snowman, how many candies will we have left?

Third calculation:

A little more complicated this one. If we have five snowmen from which we subtract two Santa Clauses who we will first multiply by three elves, how many candies will we have left?

Don't worry, it's easier than you think, provided you've solved the little introductory riddle!

RESULTS

Introductory riddle: 8 (an elf worth 1 and a Santa Claus worth 7)

First calculation: 44 candies (2 x 7 + 30)

Second calculation: 70 candies ((20 x 7) – (7 x 1 x 10))

Third calculation: 8 candies ((5 x 10) – (2 x 7) x (3 x 1))

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